Question

Please answer these question 28.

Answer 1

x + y + z = 0

=> x + y = - z ----------(1)

On cubing both sides, we get

x^3 + y^3 + 3xy ( x +y) = - z^3

=> x^3 + y^3 + 3xy ( - z) = - z^3

=> x^3 + y^3 - 3xyz = - z^3

=> x^3 + y^3 + z^3 = 3xyz

Answer 2

Proof we know that

x³ + y³ + z³- 3xyz = ( x + y + c ) ( x² + y² + z² - xy - yz - zx )

Putting x + y + z = 0 on R.H.S ., we get

x³ + y³ + z³ - 3xyz = 0

x³ + y³ + z³ = 3xyz