Question

please answer these question​

Answer 1

Answer:

[c]=0

Step-by-step explanation:

We know that,

x³-y³=(x-y)(x²+xy+y²)........................1

Given that,

x/y+y/x=-1

(x²+y²)/xy=-1

x²+y²=-xy

x²+y²+xy=0

(x²+xy+y²)=0

Multiplying by (x-y) on both sides we get,

(x-y)(x²+xy+y²)=(x-y)×0

By eq1 we get,

x³-y³=0

Hence x³-y³=0.