please answer these question
Answers
Step-by-step explanation:
Total number of balls in first bag = 10 + 12 = 22
Total number of balls in 2nd bag = 15 + 7 = 22
A) Probability of getting yellow balls frok first bag
Total Yellow balls / total no of balls
12 / 22
6 /11 or 0.55
B) Probability of getting yellow ball from 2nd bag
Total yellow ball / total number of balls
7/22
C) Probability of getting Yellow balls from a single bag
Total number of yellow balls / total number of ball
Total yellow balls = 12 + 7 = 19
Total balls of all colors =22 + 22 = 44
Probability of yellow = 19 / 44
Answer:
In bag 1
no of blue balls=10
no. of yellow balls=12
In bag 2
no. of blue balls=15
no.of yellow balls=7
a)
total no. of possible outcomes= 22
no. of favourable outcomes= 12
P(of getting yellow ball from bag 1)=12/22=6/11
b)
total no. of possible outcomes= 22
no. of favourable outcomes=7
P ( of getting yellow ball from bag 2)= 7/22
c)
total no of possible outcomes=44
no. of favourable outcomes= 7+12=19
P(of getting yellow ball)=19/44