Please answer these question no 11
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yes.......wait. in number one there is no part shaded....it's wrong question
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here's ur answer...
1. area of triangle PDQ=1/2×b×h
=1/2×6×10
=3×10
=30cm²
area of triangle PCB=1/2×b×h
=1/2×8×10
=4×10
=40cm²
area of ABCD=l×b
=18×10
=180cm²
area of unshaded portion=180-(40+30)
=180-70
=110cm²
there is no shaded portion in the 1st figure but I think qpba is the unshaded portion because I had done this question before.
2. area of DGX= 1/2×b×h
=1/2×20×40
=10×40
=400cm²
area of xye=1/2×b×h
=1/2×20×20
=10×20
=200cm²
area of GFY=1/2×b×h
=1/2×20×40
=10×40
=400cm²
area of defg= side×side
=40×40
=1600cm²
area of unshaded portion=1600-(400+200+400)
=1600-1000
=600cm²
hope this helps u...
1. area of triangle PDQ=1/2×b×h
=1/2×6×10
=3×10
=30cm²
area of triangle PCB=1/2×b×h
=1/2×8×10
=4×10
=40cm²
area of ABCD=l×b
=18×10
=180cm²
area of unshaded portion=180-(40+30)
=180-70
=110cm²
there is no shaded portion in the 1st figure but I think qpba is the unshaded portion because I had done this question before.
2. area of DGX= 1/2×b×h
=1/2×20×40
=10×40
=400cm²
area of xye=1/2×b×h
=1/2×20×20
=10×20
=200cm²
area of GFY=1/2×b×h
=1/2×20×40
=10×40
=400cm²
area of defg= side×side
=40×40
=1600cm²
area of unshaded portion=1600-(400+200+400)
=1600-1000
=600cm²
hope this helps u...
fattu2:
And thank you for the right answer
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