Question

please answer these question very fastly please ​

Answer 1

Answer:

i) 50deg ii) 80deg iii) <abc=40deg, <bca=70deg, <bac=70deg

Step-by-step explanation:

i) In triangle AOC,

AO = OC [Radii of the same circle]

<OAC = <OCA [Opp. angles to equal sides of a triangle]

Hence, <OCA = 50deg

ii) In triangle AOC,

<OAC = 50deg, <OCA = 50deg

By angle sum property in triangle AOC,

<AOC = 80deg

iii) <BCA = <OCA+<OCB

              = 50+20

              = 70deg

BY SOME CIRCLE PROPERTY, I DON'T REMEMBER THE NAME,

<AOC=2<ABC

80DEG=2