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(1)
-->Given,
u=+6m/s
a=-1m/s
-->To find:-
(a)Distance travelled before coming to rest
(b) Time taken?
SOLUTION:-
(a)Using the equation v²=u²+2aS (v=0 m/s since the body comes to rest)
v²=u²+2aS
0²=(+6)²+2*(-1)*S
0 =36-2*S
-36=-2*S
S=36/2=18m
Ans. (a)=18 m
(b)Now,
S=18m
t=?
=Using v=u+at
0=6-1*t
t=6 sec
Ans.(b)= 6sec
(2)
Since the motion is uniform the velocity will be still 10m/s
Hope that helps you
-->Given,
u=+6m/s
a=-1m/s
-->To find:-
(a)Distance travelled before coming to rest
(b) Time taken?
SOLUTION:-
(a)Using the equation v²=u²+2aS (v=0 m/s since the body comes to rest)
v²=u²+2aS
0²=(+6)²+2*(-1)*S
0 =36-2*S
-36=-2*S
S=36/2=18m
Ans. (a)=18 m
(b)Now,
S=18m
t=?
=Using v=u+at
0=6-1*t
t=6 sec
Ans.(b)= 6sec
(2)
Since the motion is uniform the velocity will be still 10m/s
Hope that helps you
abhigyan112002oyioa3:
phy, chem, math, comp
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