Math, asked by saanj6227, 8 hours ago

please answer these questions​

Attachments:

Answers

Answered by farhanahmad2608
0

Answer:

55559+99999-22225553

Answered by mitaliduggal
0

Answer:

using distant formula the distance b/w these points is

\sqrt{(5 \sin(60) - 0)^{2} + (5 \sin(30) - 0)^{2} }

(5sin(60)−0)

2

+(5sin(30)−0)

2

\sqrt{25 { \sin(60) }^{2} + 25 { \sin(30) }^{2} }

25sin(60)

2

+25sin(30)

2

\sqrt{25( { \sin(60) }^{2} + { \cos(60) }^{2} ) }

25(sin(60)

2

+cos(60)

2

)

\sqrt{25}

25

55

Similar questions