Geography, asked by aravinda67, 1 year ago

please answer these questions

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Answered by JagdishGadhvi07
0
Because surface of a sphere increases as square of its radius, both gravitational and electric forces decrease as square of the distance. So the answer to your question is - decreases by a factor of 16.
Answered by DodieZollner
0

Force of attraction due to gravity is known as

(1) f = G * m1 * m2r2f = G * m1 * m2r2

Now when the mass of both bodies is reduced to half, the resultant force is

fnew = G * m12 * m22r2fnew = G * m12 * m22r2

fnew = f4fnew = f4

The force of attraction reduces by a factor of 4

As the attraction force between the two bodies is proportional to the inverse of the square of them, if this distance is multiplied by 4, the attraction force is divided by 16

(2) The answer to this question is following:

m₁ = m₂ = 20kg

r = 50cm or 0.5m

G = 6.67 x 10⁻¹¹

formula of force

F = Gm₁m / r²

= 6.67 x 10⁻¹¹ x 20 x 20 / 0.5

= 1.067 x 10⁻⁷

(3)

g

: Acceleration due to gravity is the acceleration acquired by a body due to the earth's gravitational pull on it.

: g is a vector quantity

: It is different in different places on the surface of the earth is also different from one celestial body to another

G

: Gravitational constant is mathematically equivalent to the force of attraction between two masses of 1kg that are separated by a distance of 1m.

: G is a scalar quantity

: The G is a universal constant i.e its value the same (i.e.6.67 × 10 ^ -11 nm ^ 2kg ^ 2) everywhere is the universe

(4) It is your weight that will change

Your weight on Earth is (75 kg * 9.8 m / s ^ 2)  

while your weight on the moon is (75kg * 1.63m / s ^ 2).  

Simplifying the designated multiplications gives us these results: Your weight on Earth is 735 newtons whereas that on the moon is 122 newtons.

(5) Free fall is the term that is used to describe a falling object. Objects with a free-fall  accelerate at a rate of 9.8 m / s / s

Motion of a body projected vertically upwards

h = ut-0.5 gt ^ 2


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