Question

PLEASE ANSWER THESE QUESTIONS
AS SOON AS POSSIBLE.

Answer 1

Answer:

Explanation:

1. given the mass of solute (salt) = 2.5 g

and mass of solvent (water) = 50g

as we know that mass of solution = mass of solute + mass of solvent

= 2.5 + 50

= 52.5g

concentration of the solution = (mass of solute/mass of solution) × 100

= (2.5/52.5) × 100

= 250/52.5

= 4.76% (approximately)

2.Given :

Mass of solute = 15 g

Mass % = 15 g

We know :

Mass % = ( mass of solute / mass of solution ) × 100

We can write :

Mass of solution = mass of solute + mass of solvent

Let :

Mass of solvent = y gram :

= > 15  = ( 15 ) / ( 15 + y ) × 100

= > 1  = ( 1 ) / ( 15 + y ) × 100

= > 15 + y = 100

= > y = 85 g

We know :

Density = Mass / Volume

= > Volume = mass / density :

Density of water = 1 g / mL

= > Volume = 85 / 1 mL

= > Volume = 85 mL

3. 15% alcohol solution means that there is 15 mL of alcohol present in the 100 mL of alcohol solution

4. As given in the question,

Volume of solute = 25 ml

Volume of Solvent = 150 ml

Volume of Solution = Volume of Solute + Volume of Solvent

= 25 ml + 150 ml

= 175 ml

Volume by Volume percentage = Volume of Solute/ Volume of Solution * 100

= 25 * 100 / 175

= 14.28

5. Here, mass of solute = 21.5g whereas mass of solvent is 60g.

Given, the temperature of solubility is 25 degree Celsius.

Since, Mass of solute/ mass of solvent x temperature = solubility of the mixture

Solubility of the mixture = 21.5/60 x 25 = 8.96

Regards Faheem