Question

Please answer these questions don't spam urgent, step by step, please answer i will make u brainliest ​

Answer 1

Answer:

Step-by-step explanation:

 { a²-b²=(a-b)(a+b) }

49x² -9² = 7²x²-9² = (7x²) - (9)² = (7x-9) (7x+9)          

16x²-25 = 4²x² - 5² = (4x)²- (5)² = (4x-5)(4x+5)

{  (a-b)² = a²- 2ab + b²   }

x²-2x-1 = x²-2(x)(1) + 1² = (x-1)² = (x-1) (x-1)

9x²- 6x + 1 = (3x)²- 2 (3x)(1) +1² = (3x-1)² = (3x-1)(3x-1)

 { a²-b²=(a-b)(a+b) }

x²- (y+z)² = (x + y+z) (x- (y+z)) = (x+y+z)(x-y-z)

Answer 2

Step-by-step explanation:

$a) \: \: \: \: \: \: \: \: \: \: \: \: 49x {}^{2} - 9 {}^{2} \\ \\ = (7x) ^{2} - (9) {}^{2} \\ \\ = (7x + 9)(7x - 9) \\ \\ b) \: \: \: \: \: \: \: \: \: \: \: \: \: 16x {}^{2} - 25 \\ \\ =( 4x) {}^{2} - (5) {}^{2} \\ \\ = (4x + 5)(4x - 5) \\ \\ \\ \\c) \: \: \: \: \: \: \: \: \: x { }^{2} - 2x + 1 \\ \\ = (x {})^{2} - 2.x.1 + (1) {}^{2} \\ \\ = (x - 1) {}^{2} \\ \\ d) \: \: \: \: \: \: \: \: \: \: \: 9x {}^{2} - 6x + 1 \\ \\ =( 3x) {}^{2} - 2.3x.1 + (1) {}^{2} \\ \\ = (3x - 1) {}^{2} \\ \\ e)x {}^{2} - (y + z) {}^{2} \\ \\ = (x + y + z)(x - y - z) \\ \\ \\ \\ formula \: \: - \: \:1.( x {}^{2} - y {}^{2}) = (x + y)(x - y) \\ \\ \: \: \: \: 2.(x {}^{2} - 2.x.y + y {}^{2} ) =( x - y) {}^{2}$