please answer these questions fast
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Angle QAP=35°
Angle BAC=Angle QAP=35°(Vertically opposite angle)
Angle BCA=180°–AngleDCA(Linear pair)
=180°–110°
=70°
Angle BAC+Angle ABC+Angle BCA=180°(Angle sum property)
35°+90°+Angle ABC=180°
Angle ABC=180°–105°
=75°
Therefore, Angle ABC=75°
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