Math, asked by ajaibsingh3512531, 9 months ago


please answer these questions fast ​

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Answered by Anonymous
1

Angle QAP=35°

Angle BAC=Angle QAP=35°(Vertically opposite angle)

Angle BCA=180°–AngleDCA(Linear pair)

=180°–110°

=70°

Angle BAC+Angle ABC+Angle BCA=180°(Angle sum property)

35°+90°+Angle ABC=180°

Angle ABC=180°–105°

=75°

Therefore, Angle ABC=75°

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