Question

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Answer 1

[17]

Given :-

» 10^6 atoms weight 1.76×10^-16 gm.

Therefore,

» 1 atom will weight = [(1.76×10^-16)/10^6] = 1.76×10^-22 gm

____________

We know that :-

=> 1.66×10^-24 gm = 1 amu

so,

$= > 1.76 \times {10}^{ - 22} = \frac{1.76 \times {10}^{ - 22} }{1.66 \times {10}^{ - 24} } \: amu \\ \\ = > 1.6 \times 100 \: amu \\ \\ = > 106 \: amu$
______________[ANSWER]

Thus atomic mass of silver = 106 amu

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[18]

» The balance reaction for the formation of CO2 is :-

C + O2 ==> CO2

» and For the formation of CO is

2C + O2 ==> 2CO

______________

» moles of CO2 in 88 gm of CO2 is = 88/44 = 2

» Hence 2 moles of O2 being used for the Formation of CO2

Now,

» 1 mole of O2 will give two moles of CO gas

» Hence molecular weight of CO gas is 28 gm/mol

» moles of O2 consumed in Formation of =
2× moles of CO formed

» Hence, 4 mole of CO gas is formed amount would be = 4×28 gm = 112 gm

_________[ANSWER]

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