Please answer these questions please
Answers
Answer:
1. 180-30-80= 70°
Step-by-step explanation:
2. let the angles be x.
2x+80=180= 2x=100 = x= 50°
3. let the ratio of the angles be x.
so, x+2x+x = 180
= 4x=180
=x= 45°
so the angles of the triangle are 45°,90°,45°.
hope this helps u
★Question
1) Two angles of a triangle are 30° and 80°. Find the third angle.
Let the third angle be x.
Sum of all angles in a triangle = 180°
30° + 80° + x = 180°
110° + x = 180°
x = 180° - 110°
x = 70°
Therefore, third angle = 70°
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★Question
2) One of the angles of a triangle is 80° and the other two angle are equal. Find the measure of each of the equal angles. by
One of the angle = 80°
Other two equal angles be x.
Sum of all angles in a triangle = 180°
80° + x + x = 180°
80° + 2x = 180°
2x = 180° - 80°
2x = 100°
x = 100/2
x = 50°
Therefore, the two equal angles = 50°
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★Question
3) The three angles of a triangle are in the ratio 1:2:1. Find all the angles of the triangle. Classify the triangle in two different ways.
Let it be ∆ABC
Let the three angles be ∠A= 1x, ∠B= 2x and ∠C= 1x.
Sum of all angles in a triangle = 180°
1x + 2x + 1x = 180°
4x = 180°
x = 180°/4
x =45°
Therefore the three angles are:
∠A = 1x = 1×45 = 45°
∠B = 2x = 2 × 45 = 90°
∠C = 1x = 1×45 = 45°
Since ∠A = ∠C, ∆ABC is isosceles.
Since ∠B = 90°, ∆ABC is right angled at ∠B.
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