Physics, asked by ƒaiŗƴ, 9 months ago

please Answer these Questions step by step.............​

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Answers

Answered by anushkasharma8840
5

Answer:- 2

Projection of given vector on Y-Z plane will be

r = 1j \: + 2k

Magnitude :

m =  \sqrt{ {1}^{2}  +   {2}^{2} }

 =  >  \sqrt{1 + 4}

 =  >  \sqrt{5}

Answer :- 3

Projection of given vector on X-Z plane will be

r = 2k + 3i

Magnitude:-

m =  \sqrt{ {2}^{2} +  {3}^{2}  }

 =  >  \sqrt{4 + 9}

 =  >  \sqrt{13}

Answer :- 4

2  \sqrt{5}

Answer 4 In Attacment please Cheak It :-

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Answered by thekkechirayilamrita
1

Answer:

which class is this o don't know sorry

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