please answer these questions.
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answer of 3 question.....
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1
Answer:
17.320
Step-by-step explanation:
refer the attached figure
AB=height of tower
BC=30m
<ACB=30°
In ∆ABC
tan teta= prependicular/base
tan30°=BA/BC
tan30°×BC=AB
30×1/√3=AB
AB=17.320
Hence the height of the tower is 17.320m.
5 th question.
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