Question

Please answer these questions, urgent, please do not spam, step by step , please answer ​

Answer 1

Answer:

1) 9

Step-by-step explanation:

as it is x^2 it's transfered to the right hand side, which is 3.

so 3^2=9

Answer 2

Answer:

$x + \frac{1}{x} = 3 \\ \\ (x + \frac{1}{x} ) {}^{2} = 9 \\ \\ x {}^{2} + \frac{1}{x {}^{2} } + 2.x. \frac{1}{x} = 9 \\ \\ x {}^{2} + \frac{1}{x {}^{2} } = 9 - 2 \\ \\ x {}^{2} + \frac{1}{x {}^{2} } = 7 \\ \\ b)x - \frac{1}{x} = 4 \\ \\ (x - \frac{1}{x} ) {}^{2} = 16 \\ \\ x {}^{2} + \frac{1}{x {}^{2} } - 2.x. \frac{1}{x} = 16 \\ \\ x {}^{2} + \frac{1}{x {}^{2} } = 16 + 2 \\ \\ \: \: \: = 18 \\ \\ c)(x + y) = 4 \\ \\ (x + y) {}^{2} = 16 \\ \\ x {}^{2} + y {}^{2} + 2.x.y = 16 \\ \\ x {}^{2} + y {}^{2} + 2.3 = 16 \\ \\ x {}^{2} + y {}^{2} = 16 - 6 \\ \\ \: \: \: = 10 \\ \\ \\ d)x {}^{2} + \frac{1}{x {}^{2} } = 9 \\ \\ (x {}^{2} + \frac{1}{x {}^{2} } ) {}^{2} = 81 \\ \\ x {}^{4} + \frac{1}{x {}^{4} } + 2.x {}^{2} . \frac{1}{x {}^{2} } = 81 \\ \\ x {}^{4} + \frac{1}{x {}^{4} } = 81 - 2 \\ \\ \: \: \: = 79 \\ \\ \\ formula \: \: - \: \: \: (x + y) {}^{2} = x {}^{2} + y {}^{2} + 2.x.y \\ \\ (x - y) {}^{2} = x {}^{2} + y {}^{2} - 2.x.y$