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Question of class 8..
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(8)A+B+C+D=360
orA+B+100+60=360
orA+B+160=360
orA+B=360-160
or A+B=200
or 1/2(A+B)=200/2
or (1/2)A+(1/2)B=100
Now in triangle APB,
(1/2)A+((1/2)B+angle APB=180
or 100+angle APB=180
or angle APB=180-100
or angle APB=80
(7)Let mesures of equal angles of the quadrilateral be x
therefore
115+45+x+x=360
or 160+2x=360
or2x=360-160
or2x=200
or x=200/2
or x=100
Therefore mesure of each of equal angles is 100 degree
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