Question

Please answer these three que
1.the sum of two numbers is 95.if one exceeds the other by 15, find the numbers.

2.the numerator of a rational number is 8 less than its denominator. If the numerator is imcreased by 2 and denominator is decreased by 1, the number obtained is 1/2.find the number.

3.the present ages of rohit and mayanak are in the ratio 11:8 . 8years the sum of their ages will be 54 years. What are their present ages?

Answer 1

Answer:

1. 40,55
2. 11
3. 22,16

Step-by-step explanation:

LET THE NUMBERS BE "X" &"Y"

1.)THEY HAVE SAID THAT THEIR SUM IS 95 AND ONE OF IT EXCEEDS THE OTHER BY 15,SO:

x+y=95

x+x+15=95

2x=80

X=40

X+15=55

2.) LET THE DENOMINATOR BE "X" AND WE GET NUMERATOR AS "X-8"

WE GET THE FRACTION LIKE :  X-8/X

NOW,THE NUMERATOR HAS BEEN INCREASED BY 2 AND DENOMINATOR IS REDUCED BY 1 ANDWE GET THE ANS AS 1/2,SO THE EQUATION IS :

X-8+2/X-1 = 1/2

X-6/X-1 = 1/2

by cross multiplication;

2(X-6) = 1(X-1)

2X-12 = X-1

X=11

3.)LETTHE PRESENT AGE OF ROHIT IS "11X" AND AGE OF MAYANAK IS "8X"

RATIO OF PRESENT AGES = 11 : 8

AFTER 8 YRS THEIR AGES = 11X+8 & 8X+8

GIVEN THAT SUMOF THEIR AGES AFTER 8 TRS IS 54; SO WE THE EQUATION:

11X+8+8X+8 = 54

19X+16 = 54

19X = 54-16

19X = 38

X=2

PRESENT AGE OF ROHIT = 11X= 11(2) = 22YRS

PRESENT AGE OF MAYANAK = 8X =8(2) =16YRS