Question

please answer these two questions ​

Answer 1

Question :-

The LCM and HCF of two numbers are 6055 and 173 respectively . If one of the numbers is 267 , find the other number ?

Answer :-

Given :-

LCM and HCF of two numbers are 6055 and 173

One of the number = 267

Required to find :-

• Other number ?

Formula used :-

$\large{\dagger{\boxed{\sf{ HCF \times LCM = Product \; of \; two \; numbers }}}}$

Solution :-

Given that :-

LCM = 6055

HCF = 173

One of the number = 267

We need to find the other number

Using the formula ,

$\large{\dagger{\boxed{\sf{ HCF \times LCM = Product \; of \; two \; numbers }}}}$

So,

$\longrightarrow{\rm{173 \times 6055 }}$

$\longrightarrow{\rm{ 10,47,515}}$

However,

Let the other number be " x "

So,

According to problem

$\textsf{ one number x other number = product of two numbers }$

$\longrightarrow{\rm{ 267 \times x = 10,47,515}}$

$\longrightarrow{\rm{ x = \dfrac{1047515}{267} }}$

$\longrightarrow{\rm{ x = 3923.277 - - - }}$

$\longrightarrow{\rm{ x = 3923.28 \: ( approximately ) }}$

Therefore,

Other number = x = 3,923.28

$\rule{400}{4}$

Question :-

The LCM of two numbers is 525 and 945 is 4725 . Find their HCF ?

Answer :-

Given :-

LCM of 525 and 945 is 4725

Required to find :-

• HCF ( Highest common factor )

Formula used :-

$\large{\dagger{\boxed{\sf{ HCF \times LCM = Product \; of \; two \; numbers }}}}$

Solution :-

Given that :-

LCM of two numbers is 525 and 945 is 4725

We need to find the HCF of the given numbers

So,

Using the formula ,

$\large{\dagger{\boxed{\sf{ HCF \times LCM = Product \; of \; two \; numbers }}}}$

This formula enables us to find the HCF of the given numbers .

So,

According to problems ;

Product of two numbers = 525 x 945

=> 496,125

However,

Let the HCF be as " x "

So,

Substitute these values in the formula

$\longrightarrow{\tt{ x \times 4725 = 496125 }}$

$\longrightarrow{\tt{ 4725x = 496125 }}$

$\longrightarrow{\tt{ x = \dfrac{ 496125}{4725}}}$

$\longrightarrow{\tt{ x = 105 }}$

Therefore,

HCF = x = 105