Math, asked by Srishtidravid15, 8 months ago

please answer these two questions .
It's very very urgent please ​

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Answers

Answered by psychogirl85
1

Answer:

p^2-q^2

Step-by-step explanation:

  • x^2=(p sec a+q tan a)^2
  • =p^2tan^a+q^2sec^a+2 pq sec a tan a)
  • y^2=p^2 tan ^a+q^2 sec ^a+2pq tan a sec a
  • x^2-y^2=p^2(sec ^2 a-tan^2 a)+q^2(tan^a -sec^a)+2pq sec a tan a- 2 pq sec a tan a
  • =p^2_q^2
  • (because sec^2 a- tan^2 a=1)
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