Math, asked by SidhanthKothapalli, 6 months ago

Please answer these two questions QUICKLY!!!!!

1) Find the value of K in : (2/3)^3*(2/3)^6 = (4/9)^2k-3
Simplify and write in exponential form:
a) (3^5/3^2)*3^10
b) 8^2/2^3

Answers

Answered by yogesharma1977
0

Answer:

1)3+6=2(2k-3)

9=4k-6

9+6=4k

15/4=k

a)3^5-2×3^10

3^3×3^10

3^3+10

3^13

b)(2^3)2/2^3

2^6/2^3

2^6-3

2^3

8

Step-by-step explanation:

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