please answer these two questions with steps.i. e. proof.
do the answers in a paper and send the image please....
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value of 1/√3
Rationalizing we get
=(1/√3)x(√3/√3)
= √3/(√3x√3)
=√3/3
=1.732/3
=0.577 approx.
value of √3/√6
we can write √6 = √(2x3)= √2x√3
therefore √3/√6= √3/(√2x√3)= 1/√2
rationalising. 1/√2
= (1/√2)x (√2/√2)
= √2/(√2x√2)
= √2/2
= 1.414/2
= 0.707
Rationalizing we get
=(1/√3)x(√3/√3)
= √3/(√3x√3)
=√3/3
=1.732/3
=0.577 approx.
value of √3/√6
we can write √6 = √(2x3)= √2x√3
therefore √3/√6= √3/(√2x√3)= 1/√2
rationalising. 1/√2
= (1/√2)x (√2/√2)
= √2/(√2x√2)
= √2/2
= 1.414/2
= 0.707
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