Question

please answer this ​

Answer 1

Answer:

$cot \alpha = \frac{1}{ \sqrt{3} } \\ \\ sin \alpha = \frac{ \sqrt{3} }{2} \: \: cos \alpha = \frac{1}{2} \\ \\ l.h.s. = \frac{1 - {cos}^{2} \alpha }{2 - {sin}^{2} \alpha } = \frac{1 - \frac{1}{4} }{2 - \frac{3}{4} } \\ = \frac{ \frac{3}{4} }{ \frac{5}{4} } = \frac{3}{5}$

hence proved

Answer 2

answer is in picture please mark Answer as briain list