Chemistry, asked by Anshul0981, 2 months ago

Please Answer This 2 Questions​

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Answered by itxhorror
0

1 )

The total sum of the masses of the atoms or elements present in the molecule is termed as molecular mass.

i) Molecular mass of H2= 2 x Atomic mass of H

= 2 x 1

Molecular mass of H2 = 2 u

ii) Molecular mass of O2= 2 x Atomic mass of O

= 2 x 16

Molecular mass of O2= 32 u

iii) Molecular mass of Cl2= 2 x Atomic mass of Cl

= 2 x 35.5

Molecular mass of Cl2 = 71 u

iv) Molecular mass of CO2= Atomic mass of C + 2 x Atomic mass of O

= 12 + 2 x 16

Molecular mass of CO2 = 44 u

v) Molecular mass of CH4= Atomic mass of C + 4 x Atomic mass of H

= 12 + 4 x 1

Molecular mass of CH4 = 16 u

vi) Molecular mass of C2H6= 2 x Atomic mass of C + 6 x Atomic mass of H

= 2 x 12 + 6 x 1

Molecular mass of C2H6 = 30 u

vii) Molecular mass of C2H4= 2 x Atomic mass of C + 4 x Atomic mass of H

= 2 x 12 + 4 x 1

Molecular mass of C2H4 = 28 u

viii) Molecular mass of NH3= Atomic mass of N + 3 x Atomic mass of H

= 14 + 3 x 1

Molecular mass of NH3 = 17 u

ix) Molecular mass of CH3OH= Atomic mass of C + 4 x Atomic mass of H + 1 x Atomic mass of

= 12 + 4 x 1 + 16

Molecular mass of CH3OH = 32 u

2) Formula unit mass is defined as the sum of the atomic masses of all atoms that are present in a formula unit of the given compound.

Atomic mass of Zn = 65u

Atomic mass of Na = 23u

Atomic mass of K = 39u

Atomic mass of C = 12u

Atomic mass of O = 16u

Calculating the formula unit masses of the given compounds:

ZnO = Zn + O

ZnO = (65 + 16)u = 81u

Na2O = 2Na + O

Na2O = [(2 x 23)+16]u

Na2O = (46 + 16)u = 62u

K2CO3 = 2K + C + 3O

K2CO3 = [(2 x 39) + 12 + (3×16)]

K2CO3 = (78 + 12 + 48)u = 138u

Hence, the formula unit mass of ZnO is 81u, Na2O is 62u and K2CO3 is 138u.

Answered by shivshmbhu1630
0

Answer:

☝️Q. no.2

Q. no. 1

Solution

verified

Verified by Toppr

Molecular mass of the given molecules are calculated below:-

H

2

= 2×1=2 g/mol

O

2

= 2×16=32 g/mol

Cl

2

= 2×35.5=71 g/mol

CO

2

= 1×C+2×16=44 g/mol

CH

4

= 1×12+4×1=16 g/mol

C

2

H

6

= 2×12+6×1=30 g/mol

C

2

H

4

= 2×12+4×1=28 g/mol

NH

3

= 1×14+3×1=17 g/mol

CH

3

OH = 1×12+4×1+1×16=32 g/mol

Q no. 2

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