Question

PLEASE ANSWER THIS......

Answer 1

Answer:

by mid point theorem,

pq||EG and PQ=1/2EG

RS||EG and RS=1/2EG

therefore

PQ||RS and PQ=RS

similarly

PS||QR and PS=QR

therefore PQRS is a ||gm

in MSON(mark the point on line FH that has the contact with S as N)

by the similar manner

MSON is a ||gm(proved)

we know that the diagonals of a rhombus bisect at 90°

and the opp. angles of parallelogram are equal

therefore

MON=90 and also MSN = 90

therefore all the angles of PQRS measure 90°

therefore PQRS is a rectangle