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Here O is the centre of circle.
Therefore, OA=OB(radius of circle)
In triangle OAB,
OA=OB
OAB=OBA
AOB+OAB+OBA=180°
100°+2*OAB=180°. (OAB=OBA)
2*OAB=80°
OAB=40°
We know that any line that joins any tangent from the centre makes a right angle with the tangent.
So,
OAT=90°
Now, OAT-OAB= BAT
90°-40°=BAT
BAT= 50°
Hope it helps! Please mark it as 'Brainliest'!
Therefore, OA=OB(radius of circle)
In triangle OAB,
OA=OB
OAB=OBA
AOB+OAB+OBA=180°
100°+2*OAB=180°. (OAB=OBA)
2*OAB=80°
OAB=40°
We know that any line that joins any tangent from the centre makes a right angle with the tangent.
So,
OAT=90°
Now, OAT-OAB= BAT
90°-40°=BAT
BAT= 50°
Hope it helps! Please mark it as 'Brainliest'!
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