Math, asked by Lavander, 1 year ago

Please answer this.
27a³+8=
p³-1000=
y³+125=

Answers

Answered by totaldreamer12361
3
27a^3 +8
=(3a)^3 +(2)^3
=(3a+2)(9a^2 - 6a+4)
------------------------
P^3 - 1000
P^3 - (10)^3
(p-10)(p^2 + 10p+100)
------------------------
Y^3+125
=y^3 +(5)^3
=(y+5)(y^2 - 5y+25)
Answered by snehitha2
0
★27a³+8

→ (3a)³+(2)³

→ (3a+2){(3a)²-(3a)(2)+2²}

→ (3a+2)(9a²-6a+4)

★p³-1000

→ (p)³-(10)³

→ (p-10){p²+10p+10²}

→ (p-10)(p²+10p+100)

★y³+125

→ (y)³+(5)³

→ (y+5){y²-(y)(5)+5²}

→ (y+5)(y²-5y+25)

Hope it helps
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