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total no. of possible outcome=36
(a) let A be the event of getting sum 7.
no. of favourable outcome=5 i.e. (3,4), (4,3), (4,3), (5,2), (6,1)
P(A)=5/36
(b) let B be the event of getting sum is the perfect square.
no. of favourable outcome=7 i.e. (1,3), (1,3), (2,2), (2,2), (5,4), (6,3), (6,3)
P(B)=7/36
(a) let A be the event of getting sum 7.
no. of favourable outcome=5 i.e. (3,4), (4,3), (4,3), (5,2), (6,1)
P(A)=5/36
(b) let B be the event of getting sum is the perfect square.
no. of favourable outcome=7 i.e. (1,3), (1,3), (2,2), (2,2), (5,4), (6,3), (6,3)
P(B)=7/36
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