Math, asked by anjali06, 1 year ago

Please answer this.. ..

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Ankitgodara53: hi

Answers

Answered by VemugantiRahul
3
\mathbb{\underline{\green{Points\: to\: Remember:}}}

tan θ = \frac{sin θ}{cos θ}

cot θ = \frac{cos θ}{sin θ}

 sin^{2} θ + cos^{2} θ = 1

sin^{2} θ - cos^{2} θ = 2sin^{2} θ - 1

\mathcal{\red{\underline{\purple{SOLUTION:}}}}

\mathcal{\underline{\blue{L.H.S}}}

= tan θ - cot θ

= \frac{sin θ}{cos θ} - \frac{cos θ}{sin θ}

= \frac{sin^{2} θ - cos^{2} θ}{sin θ . cos θ}

= \frac{2sin^{2} θ - 1}{sin θ . cos θ}

= \mathcal{\underline{\blue{R.H.S}}}

\mathfrak{\huge{\pink{Cheers}}}

\mathcal{\huge{\orange{Hope\: it\: Helps}}}
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