please answer this ............ ....
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picture is not clear write measurements that are important write in comment I will read and edit my answer
ishita2688:
you have to solve problem no. 11
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Area of Four walls = 2(l+b)h
Given, Length (l) = 12 m
Breadth (b) = 8 m
Height (h) = 4m
Now, put this on Formula,
=> C.S.A = 2(12+8) x 4
=> C.S.A = (2 x 20 x 4) m^2
=> C.S.A = 160 m^2
Now, Cost of Washing 4 walls = Rs (160 x 15)
=> Cost = Rs 2400
Again,
The ceiling of room is in the form of Rectangle,
=> Ar(Rectangle) = l x b
=> Ar (Rectangle) = 12 x 8 m^2
=> Ar(Rectangle) = 96 m^2
Cost of Washing Ceiling = Rs (96 x 15) = Rs 1440
Hence, Total cost of Washing = Cost of 4 wall + Cost of Ceiling
=> Total Cost = Rs (2400 +1440)
=> Total Cost = Rs 3840
Be Brainly
Given, Length (l) = 12 m
Breadth (b) = 8 m
Height (h) = 4m
Now, put this on Formula,
=> C.S.A = 2(12+8) x 4
=> C.S.A = (2 x 20 x 4) m^2
=> C.S.A = 160 m^2
Now, Cost of Washing 4 walls = Rs (160 x 15)
=> Cost = Rs 2400
Again,
The ceiling of room is in the form of Rectangle,
=> Ar(Rectangle) = l x b
=> Ar (Rectangle) = 12 x 8 m^2
=> Ar(Rectangle) = 96 m^2
Cost of Washing Ceiling = Rs (96 x 15) = Rs 1440
Hence, Total cost of Washing = Cost of 4 wall + Cost of Ceiling
=> Total Cost = Rs (2400 +1440)
=> Total Cost = Rs 3840
Be Brainly
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