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As,
AD/BD = AE / EC
By convese of BPT,
DE Is parallel to BC
Angle D = Angle B
Angle E = Angle C
Angle D = Angle E
So Angle B = Angle C
Hence AB = AC
So, ABC is an isosceles Triangle
Hope it helps.
Mark me as brainlist.
AD/BD = AE / EC
By convese of BPT,
DE Is parallel to BC
Angle D = Angle B
Angle E = Angle C
Angle D = Angle E
So Angle B = Angle C
Hence AB = AC
So, ABC is an isosceles Triangle
Hope it helps.
Mark me as brainlist.
deepakastro:
Thank you
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please mark as brainlist answer
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