Math, asked by The2ndBrain, 1 year ago

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Answered by soumya834

sin(90-theta) =costheta
cos(90-theta)=sintheta
costheta/1+sintheta +costheta/1-sintheta
costheta(1/1+sintheta +1/1-sintheta)
costheta(1-sintheta+1+sintheta /(1-sin^2theta)
costheta(2/cos^2theta)
2/costheta
2(1/costheta)
2sectheta is answer proved

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