Math, asked by sharishk2003, 1 year ago

Please answer this...

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Answered by siddhartharao77
8

Answer:

x³ + (1/x³) = 52

Step-by-step explanation:

Given: x² + (1/x²) = 14

It can be written as,

⇒ x² + (1/x²) = 16 - 2

⇒ x² + (1/x²) + 2 = 16

⇒ (x + 1/x)² = 16

⇒ x + 1/x = 4

On cubing both sides, we get

⇒ (x + 1/x)³ = 4³

⇒ x³ + 1/x³ + 3(x + 1/x) = 64

⇒ x³ + 1/x³ + 3(4) = 64

⇒ x³ + 1/x³ + 12 = 64

x³ + 1/x³ = 52

Hope it helps!


sharishk2003: what is the formula for a^3 +b^3
siddhartharao77: a^3 + b^3 = (a + b)(a^2 - ab + b^2)
sharishk2003: but u have not chosen for
siddhartharao77: The question is asked to find x^3 + 1/x^3 !
sharishk2003: what is the formula for (a + b)^3
siddhartharao77: a^3 + b^3 + 3ab(a + b )
sharishk2003: oh thank u
siddhartharao77: Welcome
Answered by Siddharta7
1

x² + 1/x² = 14

(x + 1/x)² - 2(x)(1/x) = 14

(x + 1/x)² = 14+2

(x + 1/x)² = 16

x + 1/x = √16

x + 1/x = 4

-----------------

(x³ + 1/x³) = (x + 1/x)³ - 3(x.1/x) (x+1/x)

= 4³ - 3(4)

= 64 - 12

= 52.


sharishk2003: tq...so much
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