please answer this a question from chapter motion class 9 physics...
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Answered by
1
Answer:
Total distance covered = 20 + 5 + 30 = 55 km = 55000 m
So the average speed = total distance / total time
= 55000 / 100 = 550 m/s
(the question is not practical as the speed of sound in air ≈ 320 m/s)
Total displacement = 20 - 5 - 30 = - 15 km = -15000 m
so average velocity = total displacement / total time
= 15000 / 100
= 150 m/s
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Answered by
1
Answer:
Average speed= Total distance ÷ total time
A.S= (20+30+5) ÷ 100
A.S=0.55
Average velocity = Total displacement ÷ Total time
A.V= ((30+5)-20) ÷ 100
A.V=0.15
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