Question

PLEASE ANSWER THIS❄ Absurd answers will be reported

Answer 1

$\blue{ \large {Question:-}}$

What could be the possible height of the fisherman (AB) seen by the fish in water, complete the ray diagram.

$\purple{ \large{Answer:-}}$

As shown in diagram, due to refraction of light, the light will move away from the normal, as a result the fish will see a longer image of a fisherman "AB" as "AC". So the man will appear taller to the fish than his real height.

$\green{ \large{Explanation:-}}$

Fish is in optically denser medium i.e., water and the fisherman is in optically rarer medium i.e., air. So the rays travel from the optically rarer medium to the optically denser medium, that's why they bend towards the normal on refraction. It means that when a light rays obliquely passes from an optically rarer medium to optically denser medium, then angle of refraction is less than the angle of incidence. As the angle of incidence is more, hence the fisherman looks taller to the fish than its original/real height.

$\pink{Refractive \: index \: (n) = \frac{Real \: height}{Apparent \: height}}$

$\pink{ \therefore{Apparent \: height = \frac{Real \: hieght}{Refractive \: index \: (n)}}}$

$\orange{ADDITIONAL \: \:INFORMATION:-}$

• When a light beam travelling in air strikes at the surface of another medium, say, water, it bends from its original path at the boundary of separation of the two media. This is known as refraction of light.

• A ray of light travelling from an optically rarer medium to an optically denser medium (say,air to water), bends towards the normal on refraction. In this case, the angle of refraction is less than the angle of incidence.

$\orange{ \angle{r < { \angle{i}}}}$

• A ray of light travelling from an optically denser medium to an optically rarer medium (say, glass to air), bends away from the normal on refraction. In this case, the angle of refraction is greater than the angle of incidence.

$\orange{ \angle{r > { \angle {i}}}}$

• The refracting ability of a transparent medium is measured by its refractive index.

Answer 2

Answer:

Question:−

What could be the possible height of the fisherman (AB) seen by the fish in water, complete the ray diagram.

\purple{ \large{Answer:-}}Answer:−

As shown in diagram, due to refraction of light, the light will move away from the normal, as a result the fish will see a longer image of a fisherman "AB" as "AC". So the man will appear taller to the fish than his real height.

\green{ \large{Explanation:-}}Explanation:−

Fish is in optically denser medium i.e., water and the fisherman is in optically rarer medium i.e., air. So the rays travel from the optically rarer medium to the optically denser medium, that's why they bend towards the normal on refraction. It means that when a light rays obliquely passes from an optically rarer medium to optically denser medium, then angle of refraction is less than the angle of incidence. As the angle of incidence is more, hence the fisherman looks taller to the fish than its original/real height.

\pink{Refractive \: index \: (n) = \frac{Real \: height}{Apparent \: height}}Refractiveindex(n)=

Apparentheight

Realheight

\begin{lgathered}\pink{ \therefore{Apparent \: height = \frac{Real \: hieght}{Refractive \: index \: (n)}}}\\\\\end{lgathered}

∴Apparentheight=

Refractiveindex(n)

Realhieght

\orange{ADDITIONAL \: \:INFORMATION:-}ADDITIONALINFORMATION:−

When a light beam travelling in air strikes at the surface of another medium, say, water, it bends from its original path at the boundary of separation of the two media. This is known as refraction of light.

A ray of light travelling from an optically rarer medium to an optically denser medium (say,air to water), bends towards the normal on refraction. In this case, the angle of refraction is less than the angle of incidence.

\begin{lgathered}\orange{ \angle{r < { \angle{i}}}}\\\\\end{lgathered}

∠r<∠i

A ray of light travelling from an optically denser medium to an optically rarer medium (say, glass to air), bends away from the normal on refraction. In this case, the angle of refraction is greater than the angle of incidence.

\begin{lgathered}\orange{ \angle{r > { \angle {i}}}}\\\\\end{lgathered}

∠r>∠i

The refracting ability of a transparent medium is measured by its refractive index.