Question

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Answer 1

hey there ..attaching a picture for ur answer:

Answer 2

Given Equation is:

$\frac{1-sinA}{1+sinA}$

On rationalizing, we get

$\frac{(1-sinA)(1-sinA)}{(1+sinA)(1-sinA)}$

$\frac{(1-sinA)^2}{(1-sin^2A)}$

$\frac{(1-sinA)^2}{cos^2A}$

$( \frac{1-sinA}{cosA})^2$

$( \frac{1}{cosA} - \frac{sinA}{cosA} )^2$

$(secA - tanA)^2$



Hope this helps!