Question

please answer this and I will mark u the brainliest​

Answer 1

Answer:

sin0=1-sin20 sin0=cos20 now LHS= cos20 +cos40 cos20+(cos20)2 cos20+sin20=1 =RHS

now pls mark me as brainlist

Answer 2

Step-by-step explanation:

(sinA+2sinAcosA)/(1+cosA+2cos^2A-1)

(sinA+2sinAcosA)/(cosA+2cos^2A)

(sinA[1+2cosA])/(cosA[1+2cosA])

sinA/cosA

tanA

hence proved