Please answer this and no spam.
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Answer:
1 : 500
2500
2 : 3100
5100
3 : 5900
7900
Explanation:
The explanation is down as how the computer will perform this task:
- It will consider C as 1, 2 & 3.
- Add a punctuation sign as we told it to print.
- Now there is a complexity in SUM:
- First it will print as 0(SUM) + 1(L1[C])
- Then it will consider C then colon and then 1 and will print it with its indexed valued after a colon.
- The above process will be looped till the C is considered as 3 as it is in the for loop.
- Then it will consider SUM as 500(SUM, computer considered before) + 200(L1[0]) and multiply it with 10.
- The above process' answer will be 2500 and will be printed after 1 : 500.
- Again it will be looped until C is 3.
- We will finally get the anwer which is given above.
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