please answer this any maths genius can answer this then I will mark as brainliest
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Hope this may help me mark as brainliest
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Question : In the given figure BL is perpendicular to AC , MC is perpendicular LN , AL = CN and BL = CM .
To Prove : ∆ ABC is congruent to ∆ NML .
Solution :
Refer to the above attachment !!
There are 4 ways by which we can prove any 2 triangles as congruent :
If they are having -
★ SSS : Side Side Side
Three pairs of side are equal then the triangles are congruent.
★ ASA : Angle Side Angle / AAS : Angle Angle Side
If any 2 pairs of angles and 1 side are equal then the triangles are congruent.
★ SAS : Side Angle Side
If any two pairs of sides and the included angle are equal then the triangles are congruent.
★ RHS : Right Hypotenuse Side
If any right angle triangles are having their hypotenuse and a pair of sides equal then they are congruent.
To Prove : ∆ ABC is congruent to ∆ NML .
Solution :
Refer to the above attachment !!
There are 4 ways by which we can prove any 2 triangles as congruent :
If they are having -
★ SSS : Side Side Side
Three pairs of side are equal then the triangles are congruent.
★ ASA : Angle Side Angle / AAS : Angle Angle Side
If any 2 pairs of angles and 1 side are equal then the triangles are congruent.
★ SAS : Side Angle Side
If any two pairs of sides and the included angle are equal then the triangles are congruent.
★ RHS : Right Hypotenuse Side
If any right angle triangles are having their hypotenuse and a pair of sides equal then they are congruent.
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