Question

please answer this as soon as possible​

Answer 1

ANSWER

ab=1ms

Explanation:

ANSWER

Velocity of car A = 36km/h=36× 1000/3600=10m/s

Velocity of car B =54× 5/18 m/s -15m/s

Velocity of car C =−54km/h

=−15m/s

In the frame of reference of car A:

velocity of B with respect to A

V ba =Vb-Va

=15−(+10)

V ba =5m/s

Velocity of C with respect to A

V ca =Vc -Va =−15−(+10)

Vca =−25m/s

Therefore time taken by C to reach A

t=1000/25

=40s(Calculate in the frame of car A)

To avoid accident B will trave same relative distance in 40s

Applying : s=ut+ 1/2at2

1000=5×40× 1/2ab×(40)^2

ab=1ms