Question

please answer this ASAP
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Answer 1

Answer:

$x = \frac{3}{2} and \frac{5}{2}$

Step-by-step explanation:

By solving this we get :

${x}^{2} (x + {1})^{2} \div \: x(x + 1) = \frac{34}{15}$

${x}^{2} + {x}^{2} + 2x \:1 \div {x}^{2} = \frac{34}{15}$

$34 {x}^{2} + 34x = 15 {x}^{2} + 15 {x}^{2} + 30x + 15$

$4 {x}^{2} + 4x - 15 = 0$

By solving factorization method we get :

$4 {x}^{2} + 10x - 6x - 15 = 0$

$2x(2x + 5) -3(2x + 5) = 0$

$2x - 3 = 0$

$x = \frac{3}{2} and \: - \frac{5}{2} (as \: x \: cannot \: be \: negetive)$

$x = \frac{3}{2}$

$but \: here \: egt \: x = \frac{3}{2} and \frac{5}{2}$

Hope it's helpful to you .

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Answer 2

Answer:

hi Saniya!

Step-by-step explanation:

how are you?????