Question

please answer this below question

Answer 1

Answer:

hope this helps u

∠y= 7x-20 vertically opposite angle  

∠mrp=3x  vertically opposite angle

we know that angle  of a point is 360

∠y+ 7x-20  +∠mrp+3x = 360

7x-20 +7x-20  + 3x+3x = 360 (∠y= 7x-20 and ∠mrp=3x)

20x-40=360

20x=320

x = 320/20

x = 16

∠y= 7x-20

     = 7*16- 20

∠y = 62

∠mrp=3x

        = 3*16

∠mrp= 48

value of x+y

y =62

x = 16

x+y = 62+16=78

plz mark as brainliest answer

Answer 2

Given:

• PRQ and MRN are straight lines.
• The two lines intersect each other.

To Find:

• The value of (x+y) .

Concept Used:

• Straight line measure 180°.
• Vertically opposite angles are equal.

Answer:

Here its given that two lines PRQ and MRN intersect each other .

Now , from figure its clear that

$\sf{\angle PRN \:and\:\angle QYN }$ are angles in a straight line and form linear pair.

So , $\sf{\implies \angle PRN \:+\:\angle QYN=180^{\circ}}$

$\sf{\implies 7x-20^{\circ}+3x=180^{\circ}}$

$\sf{\implies 10x-20^{\circ}=180^{\circ}}$

$\sf{\implies 10x=180^{\circ}+20^{\circ}}$

$\sf{\implies 10x=200^{\circ}}$

$\sf{\implies x=\dfrac{200^{\circ}}{10}}$

${\underline{\boxed{\red{\sf{\leadsto x=20^{\circ}}}}}}$

Hence the measure of x is 20°.

=> 7x-20° = 7×20°-20°=140°-20°=120°.

Now ,

$\sf{\angle PRN \: and\:\angle MRQ }$ are Vertically opposite angles .

Hence they must be equal.

Hence y = 7x-20° = 120° .

Therefore x+y = 120°+20°=140°.