Question

please... answer this correctly ​

Answer 1

Explanation:

Given:-

Radius of a curvature of track =72m

Maximum speed => 216km/h = 60m/s

Width of the track= 10m

To Find:-

• The angle that the road shlould be tilted.
• The height of the outer edge of the track.

Solution:-

• The angle of banking of the road given by

TanᎾ = v^2/rg

Ꮎ = Tan^-1 (v^2/rg)

Ꮎ = Tan^-1 (60^2/72×1°)

Ꮎ = 78-69°

• The height of the outer edge of the road is given by-

SinᎾ =h/w

h= w SinᎾ

h= 10×Sin(78.69)

h= 9.805m

The angle that the road should be tilted is 78.69°

The height of the outer edge is 9.805m

Answer 2

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