Question

please answer this correctly ​

Answer 1

Step-by-step explanation:

CD² = BD² - BC² [using pythagoras theorem]

CD² = 13²-12²

CD = √25

CD = 5

so,

$\sin\phi \: = \frac{5}{13}$

now construct DE perpendicular to AB, which will be Parallel to BC, hence BCDE is a rectangle

Hence, BE = CD = 5 and DE = BC = 12

so AE = AB - BE

AE = 14-5

AE = 9

In right ∆AED,

AD² = AE²+DE²

AD² = 9²+12²

AD = √(81+144)

AD = √225

AD = 15

Now,

$\cos \theta = \frac{12}{15} \\ = \frac{4}{5} \\ \\ \tan \theta = \frac{12}{9} \\ = \frac{4}{3}$

HOPE IT HELPS :D