Question

please answer this correctly and take 50 points​

Answer 1

$\huge{\underline{\mathtt{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}$

✰ Let the sum be Rs.P

Time =2year

Time =2yearRate=8%

S.I for 2 years=

100

100P×8×2

100P×8×2

100P×8×2

100P×8×2 25

100P×8×2 254P

100P×8×2 254P

100P×8×2 254P

100P×8×2 254P C.I for 2 years=[P(1+

100P×8×2 254P C.I for 2 years=[P(1+ 100

100P×8×2 254P C.I for 2 years=[P(1+ 1008

100P×8×2 254P C.I for 2 years=[P(1+ 1008

100P×8×2 254P C.I for 2 years=[P(1+ 1008 )

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P×

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 ×

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P=

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P −

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P − 25

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P − 254P

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P − 254P

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P − 254P =64

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P − 254P =64⇒

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P − 254P =64⇒ 625

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P − 254P =64⇒ 625104P−100P

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P − 254P =64⇒ 625104P−100P

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P − 254P =64⇒ 625104P−100P =64

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P − 254P =64⇒ 625104P−100P =64⇒4P=64×625

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P − 254P =64⇒ 625104P−100P =64⇒4P=64×625⇒P=

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P − 254P =64⇒ 625104P−100P =64⇒4P=64×625⇒P= 4

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P − 254P =64⇒ 625104P−100P =64⇒4P=64×625⇒P= 464×625

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P − 254P =64⇒ 625104P−100P =64⇒4P=64×625⇒P= 464×625

100P×8×2 254P C.I for 2 years=[P(1+ 1008 ) 2 ]−P⇒[P× 100108 × 100108 ]−P⇒ 625729P −P= 625104P According to the question⇒ 625104P − 254P =64⇒ 625104P−100P =64⇒4P=64×625⇒P= 464×625 =Rs.10000

ʜᴏᴩᴇ ɪᴛ'ꜱ ʜᴇʟᴩ ᴜʜʜ :)

Answer 2

$\huge \sf{ \underline{ \pink{ \underline{ \blue{ \underline{ \pink{ \underline{ \blue{answer}}}}}}}}}$

Let the sum be Rs.P

Time =2year

Rate=8%

S.I for 2 years=100P×8×2=254P

C.I for 2 years=[P(1+1008)2]−P

⇒[P×100108×100108]−P

⇒625729P−P=625104P

According to the question

⇒625104P−254P=64

⇒625104P−100P=64

⇒4P=64×625

⇒P=464×625=Rs.10000

Thanks!❤