Question

Please answer this correctly... I'll mark you the brainliest..!!!

Answer 1

Answer:

$(k - 1)x ^{2} + kx + 1$

putting the value of the [$x= (-3)$]

$(k-1) (-3)^{3} + k(-3) + 1$ = 0

$(k-1) (-9) + (-3k) + 1$ = 0

$-9k + 9 -3k + 1$ = 0

$-12k + 10 = 0$

$-12k = -10$

$k = \frac{-10}{-12}$

$k = \frac{10}{12}$

k = 5/6 (ans)

Step-by-step explanation: