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Don't answer if u lack knowledge Q42(answer both)
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take n = 3
now n cube - n = divisible by 6
3 cube - 3 = divisible by 6
9 - 3 = divisible by 6
6 = which is divisible by 6
when u will take any number instead of 3 ....and put the value in n cube-n it will be divisible by 6 u van try too :)
now on question no 2
product of three consecutive positive integers = divisible by 6
1*2*3 = divisible by 6
6*1 = divisible by 6
6 = 6 which is divisble by 6
consecutive means 'lagathaar' u can also take 4..5..6 instead of 1...2..3 or any consecutive positive integer the product will be divisible by 6 :) hope it helps :)
now n cube - n = divisible by 6
3 cube - 3 = divisible by 6
9 - 3 = divisible by 6
6 = which is divisible by 6
when u will take any number instead of 3 ....and put the value in n cube-n it will be divisible by 6 u van try too :)
now on question no 2
product of three consecutive positive integers = divisible by 6
1*2*3 = divisible by 6
6*1 = divisible by 6
6 = 6 which is divisble by 6
consecutive means 'lagathaar' u can also take 4..5..6 instead of 1...2..3 or any consecutive positive integer the product will be divisible by 6 :) hope it helps :)
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