Please answer this equation
10th question
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Let f(x)=x³+3x²+4x+α
As (x+6) is a factor.... f(-6)=0
-216+108-24+α=0
α= 240-108= 132
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Step-by-step explanation:
HEY THERE
TO MAKE (x+6) a factor we should write p(x)
x=-6 ( factor theorem)
putting the value of x in eq.
-216+108-24+a=0
a=132
HOPE IT HELPS
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