Question

Please answer this equation

Answer 1

Rule of BODMAS :- According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right.

Solution :-

Of Part :- 2(1/4) of (2/3)

→ (9/4) * (2/3)

→ (3/2)

Now,

First Division Part :- (3/4) ÷ of Part

→ (3/4) ÷ (3/2)

→ (3/4) * (2/3)

→ (1/2) ----------------------------- Equation (1)

Now,

Second Division Part :- (1/2 - 1/3) / (1/2 + 1/3)

Taking LCM of Numerator & Denominator,

→ {(3 - 2)/6} / {(3 + 2)/6}

→ (1/6) / (5/6)

→ 1/6 * 6/5

→ (1/5)

Now,

Multiple Part :- Second Division Part * 3(1/3)

→ (1/5) * (10/3)

→ (2/3) -------------------- Equation (2).

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Now,

From Equation (1) and (2), Our Question becomes ,

→ (1/2) - (2/3) + (5/6)

Taking LCM,

→ (3 - 2*2 + 5) /6

→ (8 - 4) /6

→ (4/6)

→ (2/3) (Ans).

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Answer 2

Step-by-step explanation:

.

$hence \: answer \: is \frac{2}{3} .$

Solution :-

given :-

2(1/4) of (2/3)

=> (9/4) * (2/3)

=>(3/2)

Now,

First Division Part :-

(3/4) ÷ of Part

=> (3/4) ÷ (3/2)

=> (3/4) * (2/3)

=>(1/2) .......Eq.(1)

Now,

Second Division Part :-

(1/2 - 1/3) / (1/2 + 1/3)

Taking LCM of Numerator & Denominator,

=>{(3 - 2)/6} / {(3 + 2)/6}

=> (1/6) / (5/6)

=>1/6 ×6/5

=>(1/5)

Second Division Part ×3(1/3)

=>(1/5) ×(10/3)

=> (2/3) ....... .Equ (2).

then

From Equation (1) and (2), Our Question becomes ,

=> (1/2) - (2/3) + (5/6)

Taking LCM,

=> (3 - 2×2 + 5) /6

=>(8 - 4) /6

=>(4/6)

=>(2/3)

$hence \: answer \: is$