please answer this experts !
Answers
x² + x - 20
x² + 5x - 4x - 20
x(x+5) -4 (x+5)
(x-4) (x+5)
x² - 4x - 60
x² - 10x + 6x - 60
x(x-10) + 6(x-10)
(x+6) (x-10)
x² + 3x - 40
x² + 8x - 5x - 40
x(x+8) -5(x+8)
(x-5) (x+8)
2x² - 3x + 1
2x² - 2x - x + 1
2x(x-1) -1(x-1)
(2x-1) (x-1)
6x² - 5x - 4
6x² -8x + 3x - 4
2x(3x -4) +1(3x -4)
(2x+1) (3x-4)
hope it helps
please mark as brainliest
Step-by-step explanation:
Solutions:-
1) Given expression is x²+x-20
It can be written as
=> x²+5x-4x-20
=>x(x+5)-4(x+5)
=>(x+5)(x-4)
x²+x-20 = (x+5)(x-4)
Factorization of x²+x-20 is (x+5)(x-4)
2) Given expression is x²-4x-60
It can be written as
=> x²-10x+6x-60
=> x(x-10)+6(x-10)
=> (x-10)(x+6)
x²-4x-60 = (x-10)(x+6)
Factorization of x²-4x-60 is (x-10)(x+6)
3) Given expression is x²+3x-40
It can be written as
=> x²+8x-5x-40
=> x(x+8)-5(x+8)
=> (x+8)(x-5)
x²+3x-40 = (x+8)(x-5)
Factorization of x²+3x-40 is (x+8)(x-5)
4) Given expression is 2x²-3x+1
It can be written as
=> 2x²-2x-x+1
=> 2x(x-1)-1(x-1)
=> (x-1)(2x-1)
2x²-3x+1 = (x-1)(2x-1)
Factorization of 2x²-3x+1 is (x-1)(2x-1)
5) Given expression is 6x²-5x-4
It can be written as
=> 6x²+3x-8x-4
=> 3x(2x+1)-4(2x+1)
=> (2x+1)(3x-4)
6x²-5x-4 = (2x+1)(3x-4)
Factorization of 6x²-5x-4 is (2x+1)(3x-4)
Used Method:-
Splitting the middle